An airplane takes 4 hours to travel a distance of 3000 miles with the wind. The return trip takes 5 hours against the wind. Find the speed of the plane in still air and the speed of the wind.

Answer 1

3000 = (S+R)*4 = 4S + 4R

3000 = (S-R)*5 = 5S - 5R

0 = S - 9R

S = 9R

3000 = (9R + R)* 4 = 40R

3000/40 = R

300/4 = R

150/2 = R

R= 75

S = 9*75 = 675