C12H22O11(aq)+H2O(g)->4C2H5OH(l)+4CO2(g) Find the theoretical yield and the percent yields of ethanol if 680.g sucrose undergoes fermentation and 303.5g ethanol is obtained.

Answer 1

C₁₂H₂₂O₁₁(aq) + H₂O(g) ==> 4C₂H₅OH(l) + 4CO₂(g) ... balanced equation

moles of sucrose = 680.0 g x 1 mole/342.3 g = 1.9087 moles

Theoretical yield ethanol = 1.9087 moles sucrose x 4 moles ethanol/1 mole sucrose x 46.07 g/mol = 366 g

% yield ethanol = 303.5 g/366.1g (x100%) = 82.9%