
Glenn M. answered 10/25/14
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Let x = number of $10 checks
and y = number of $40 checks
and z = number of $50 checks
from what is given in the problem we can write down 3 equations :
x + y + z = 21
(4)z = x
10(x) + 40(y) + 50(z) = 510
solving these 3 equations , results in
x = 12 , y = 6 and z = 3