Find two consecutive even integers

Question

Find two consecutive even integers such that the smaller added to

four times the larger gives a sum of 48

Answer 1

Let the 2 consecutive even integers be x and x + 2

smaller added to four times the larger gives a sum of 48....This equates to the following equation.

x + 4(x +2) = 48

x + 4x + 8 = 48

5x = 40

x = 40 / 5 = 8 (the smaller #)

x + 2 = 8 + 2 = 10

Therefore, the 2 consecutive even integers are 8 and 10.