This differential equation can be solved by separating variables.
dy/dx = (2x-1)y => dy/y = (2x-1) dx
Integrate both sides
ln y = x2 - x + C
y=Aexp(x2 - x) where C = lnA
SInce y(1) = e, A = e
and y(x) =exp(x2 - x +1 and y(2) = e3
Lindsey A.
asked 12/05/18Please answer ASAP!! In a math battle and I haven’t learned this yet!!
This differential equation can be solved by separating variables.
dy/dx = (2x-1)y => dy/y = (2x-1) dx
Integrate both sides
ln y = x2 - x + C
y=Aexp(x2 - x) where C = lnA
SInce y(1) = e, A = e
and y(x) =exp(x2 - x +1 and y(2) = e3
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Lindsey A.
Thank you so much for answering! I was given this problem as a multiple choice question and I don't see E to the third power on there, Could it be any of these? A) 3 e B) 3e C) e/3 D) 3/e E)e312/05/18