Find 3 consecutive positive odd integers such that the product of the first and the third is 4 less than seven times the second.

Answer 1

X(X+4) = 7(X+2)-4

x^2 + 4x = 7x + 14 - 4

x^2 + 4x - 7x - 10 = 0

x^2 - 3x - 10 = 0

( x - 5 )( x + 2 ) = 0

x=5 or x=-2

5, 7, 9