Find two supplementary angles such that the measure of the first angle is 2​° less than three times the measure of the second.

Answer 1

Greetings! Lets solve this shall we ?

So, we must find two supplementary angles such that the measure of the first angle is 2 less than 3 times the second angle. This translates into

Angle A = 3x - 2

Angle B = x

Definition: The sum of two supplementary angles equal to 180 degrees! Then,

(3x - 2) + (x) = 180

4x - 2 = 180

4x = 182

x = 45.5 degrees = Angle B. Then we plug the value into Angle A to get

Angle A = 3(45.5) - 2 = 134.5 degrees

I hope this helped!