a[1 + r + ...r8] = a(1 - ar9)/(1-r) where r = -2
684 = a[1 - (-2)9]/[1 - (-2)] = a(513/3) = 171a and a = 4
The first term is 4 and the 8th term is and the 8th term is -512
Alexa M.
asked 12/02/18I'm not sure if a geometric progression is the same as a geometric sequence. Let me know if my answers are correct or how I should go about solving it.
a[1 + r + ...r8] = a(1 - ar9)/(1-r) where r = -2
684 = a[1 - (-2)9]/[1 - (-2)] = a(513/3) = 171a and a = 4
The first term is 4 and the 8th term is and the 8th term is -512
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