Aloke S.
asked • 11/28/18If a1=4, a2 =3, and a_n=a_{n-1}+2a_{n-2}, then find the value of a6.
More
1 Expert Answer
an = an-1 + 2an-2 a1 = 4 a2 = 3
a3 = a2 + 2a1 = 3 + 2(4) = 11
a4 = a3 + 2a2 = 11 + 2(3) = 17
a5 = a4 + 2a3 = 17 + 2(11) = 39
a6 = a5 + 2a4 = 39 + 2(17) = 73
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Arthur P.
a_3 = a_1 + a_2, so a_3 = 4 + 3 = 7. following this pattern, a_4 = 7 + 3 = 10, a_5 = 7 + 10 = 17, a_6 = 17 + 10 = 27.11/29/18