
Lauren H. answered 11/27/18
Tutor
4.8
(24)
Experienced High School Chemistry Teacher
a2b3-a3b2+a2b
(a^2b)(b^2 - ab + 1)
or,
(a^2b)(b^2 - ab + b/b)
(a^2b)(b)(b - a + 1/b)
Alfredo E.
asked 11/27/18a2b3-a3b2+a2b
Lauren H. answered 11/27/18
Experienced High School Chemistry Teacher
a2b3-a3b2+a2b
(a^2b)(b^2 - ab + 1)
or,
(a^2b)(b^2 - ab + b/b)
(a^2b)(b)(b - a + 1/b)
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