J.R. S. answered 11/26/18
Ph.D. University Professor with 10+ years Tutoring Experience
Look at the molecular equation first:
Li2CO3(aq) + 2HCl(aq) ==> 2LiCl(sq) + H2CO3(aq) ==> 2LiCl(aq) + CO2(g) + H2O(l)
From this, we can write the total ionic equation:
2Li+(aq) + CO32-(aq) + 2H+(aq) + 2Cl-(aq) ==> 2Li+(aq) + 2Cl-(aq) + CO2(g) + H2O(l)
Now we cancel the spectator ions and we are left with the net ionic equation:
CO32-(aq) + 2H+(aq) ==> CO2(g) + H2O(l)