
Russ P. answered 10/23/14
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Daniel,
I don't see your diagram, but it doesn't matter.
You say the minimum of y = f(x) occurs at (x,y) = (3,1). Hence y= f(x) >=1 for all other x in its domain of definition.
(a) y = f(x) + 3 merely increases the value y by 3 for any x, or just raises its graph up 3. The x-value for its minimum remains at x=3 and y = f(3) + 3 = 1 + 3 = 4. Hence, new minimum = (3,4)
(b) y = f(x-2) just shifts or translates the graph of f to the right by 2. So what occurred at x=3 (the minimum y) now occurs at x=5 without changing y = 1. Hence, new minimum = (5,1).
(c) y = f(1.5x) compresses the x-scale without changing y. So what happened at x=3 before now happens at x'=2 on the new scale. Thus, the minimum point now becomes (2,1).