Patrick B. answered 11/27/18
Math and computer tutor/teacher
since the average increases, the new man must weight more than 65 lbs.
Let S be the sum of the first 7 men.
The average A = (S + 65)/8
8A = S + 65
Upon replacement:
8(A+1.5) = S + 65 + x where x is the difference in the weights
8A + 1.5*8 = S + 65 + x
8A + 12 = S + 65 + x
S + 65 + 12 = S + 65 + x
x = 12
The new man weights 12 pounds more or 65+12 = 77 lbs.