dy/dx=√ (1 − y ^2). find d^2y/dx^2

Question

struggling with this problem because of the implicit differentiation.

Answer 1

dy/dx = (1-y²)^1/2

d²y / dx² = (1/2)(1-y²)^-1/2(-2y)(dy/dx)

= [-y / √(1-y²)](dy/dx)

= [-y / √(1-y²)] √(1-y²) = -y