x2 - 2y2 = 4
Let x = rcosθ and y = rsinθ
Then, r2cos2θ - 2r2sin2θ = 4
r2cos2θ - 2r2(1 - cos2θ) = 4
r2(3cos2θ - 2) = 4
r2 = 4 / (3cos2θ - 2)
Juan P.
asked 11/22/18x2 - 2y2 = 4
Let x = rcosθ and y = rsinθ
Then, r2cos2θ - 2r2sin2θ = 4
r2cos2θ - 2r2(1 - cos2θ) = 4
r2(3cos2θ - 2) = 4
r2 = 4 / (3cos2θ - 2)
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