Write an equation of the line that passes through the given point and is perpendicular to the given line of (-6,-4);y=1/3x+1

Answer 1

Greetings! Lets solve this shall we ?

So, we must find the equation of a line perpendicular to the given line y = (1/3)x + 1 such that we must modify the slope of (1/3) into m = -3. Then,

y - y1 = m(x - x1)

y - (-4) = -3(x - (-6))

y + 4 = -3(x + 6)

y + 4 = -3x - 18...................Subtract 4 to both sides such that

y = -3x - 18 - 4.............Add like terms such that

y = -3x - 22

I hope this helped!