Q: Twice the square of an integer is added to the integer and the result is 55. Find the value of the integer

Question

please help me, i need the answer today

Answer 1

Good Morning, Jasmine,

According to the information provided in your problem:

2x^2 + x = 55 "Twice the square of an integer is added to the integer and the result is 55." I used x as the integer.

Now, let's solve the equation, fair enough?

2x^2 + x - 55 = 0 Subtract 55 from both sides of your equation, okay?

(2x + 11)(x - 5) = 0 Factor the trinomial, okay?

2x + 11 = 0 Solve this equation first.

2x = -11

x = -11/2

x - 5 = 0 Solve this equation second.

x = 5

Therefore, x is equal to -11/2 or 5

I hope this assisted you and that you have a great week and Thanksgiving. If I may be of further assistance, please just reach out to me, or any tutor. Best!