Solution A is 50% acid and solution b is 80% acid. How much of each should be used to make 100cc. of a solution that is 68% acid?

Question

All help is appreciated, Thanks in advance!

Answer 1

A+B = 100

0.5A + 0.8B = 100 * 0.68 = 68

0.5A + 0.8 ( 100 - A) = 68

0.5A + 80 - 0.8A = 68

-0.3A = -12

3A = 120

A=40

40 cc of A and 60 cc of B