Lauren H. answered 11/16/18
Tutor
4.8
(24)
Experienced High School Chemistry Teacher
y = mx + b
y = 3x + b
Substitute:
-2 = 3(1) + b
-2 = 3 + b
b = -5
y = 3x -5
Let x = 0, then y = -5
Now, we have two points: (0, -5) and (1, -2)
m = (y2 - y1)/(x2 - x1)
(x2 - x1) m = (y2 - y1)
(1 - 0) 3 = (-2 - -5)