
Lauren H. answered 11/15/18
Experienced High School Chemistry Teacher
80 ≤ p ≤ 100
p = 2l + 2w
l = w + 20
p = 2(w + 20) + 2w
p = 2w + 40 + 2w
p = 4w + 40
80 ≤ p ≤ 100
80 ≤ 4w + 40 ≤ 100
or,
40 ≤ 4w ≤ 60
or,
10 ≤ w ≤ 15
Kathryn M.
asked 11/15/18The length of a rectangle is 20 meters longer than the width. The perimeter must be between 80 and 100 meters. Write and solve a compound inequality to determine the possible values for the width of the rectangle.
Lauren H. answered 11/15/18
Experienced High School Chemistry Teacher
80 ≤ p ≤ 100
p = 2l + 2w
l = w + 20
p = 2(w + 20) + 2w
p = 2w + 40 + 2w
p = 4w + 40
80 ≤ p ≤ 100
80 ≤ 4w + 40 ≤ 100
or,
40 ≤ 4w ≤ 60
or,
10 ≤ w ≤ 15
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