Lauren H. answered 11/14/18
Experienced High School Chemistry Teacher
y = mx + b
m = (8 - 0)/(0 - -2) = 8/2 = 4
y = 4x + b
substitute in set of coordinates:
0 = 4(-2) + b
0 = -8 + b
b = 8
y = 4x + 8
Sebastian A.
asked 11/14/18
Lauren H. answered 11/14/18
Experienced High School Chemistry Teacher
y = mx + b
m = (8 - 0)/(0 - -2) = 8/2 = 4
y = 4x + b
substitute in set of coordinates:
0 = 4(-2) + b
0 = -8 + b
b = 8
y = 4x + 8
Lauren H. answered 11/14/18
Experienced High School Chemistry Teacher
y = mx + b
m = (8 - 0)/(0 - -2) = 8/2 = 4
y = 4x + b
substitute in set of coordinates:
0 = 4(-2) + b
0 = -8 + b
b = 8
y = 4x + 8
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