Let L = length, W = width and P = Perimeter
W = L - 12
P = 2(L + W) = 104
L + W = 52
Substitute
L + L - 12 = 52
You finish it from here.
Scott N.
asked 11/13/18The perimeter of a rectangle is 104 inches. The width of the rectangle is 12 inches less than the length of the rectangle. Find the dimensions of the rectangle.
Let L = length, W = width and P = Perimeter
W = L - 12
P = 2(L + W) = 104
L + W = 52
Substitute
L + L - 12 = 52
You finish it from here.
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