The distance from (5,4) to (-3,2) is sqrt(82 + 22) = 2 sqrt(17)
Therefore, cd is 4 sqrt(17) and the perimeter of the regular pentagon is 20 sqrt(17).
Cici C.
asked 11/02/18a (5,4) is the midpoint of cd and d is (-3,2). if cd is one side pof a regular pentagon what is the perimieter of the pentagon
The distance from (5,4) to (-3,2) is sqrt(82 + 22) = 2 sqrt(17)
Therefore, cd is 4 sqrt(17) and the perimeter of the regular pentagon is 20 sqrt(17).
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