Two consecutive numbers exist such that twice the first number added to the second number equals 31. Find the two numbers.

Answer 1

If the first number is n, the second number will be n+1 (because they are consecutive numbers)

Twice the first number will be express as 2n, and added to the second number equals to 31 will be

expressed as 2n + (n+1) =31

Solve: 2n +n +1 =31

3n + 1 = 31

3n =31-1

3n =30

n=10 n+1 =11

Therefore, the two numbers are 10 and 11