
Philip P. answered 10/28/18
Effective and Patient Math Tutor
You don't tell us what the choices are. But 56 and 28 are both divisible by 2, 4, 7, 14, and 28. So we can factor out any of those numbers giving us the following choices:
2(-28z + 14) or -2(28z - 1)
4(-14z + 7) or -4(14z - 7)
7(-8z + 4) or -7(8z - 4)
14(-4z + 2) or you can do this one and the next
28(2z + 1)