work question please help!

Question

26 grams of N2 is placed in clyinder at 25 degrees celisus and the piston is adjusted so that the gas occupies a volume of 37.6 L. A pressure of 1.8 atm is now applied to the piston and olume compresses. how much heat flowed out of the piston asa result of compression?

Answer 1

Here is my feeble attempt:

W = -P∆V

To find ∆V we need to know the initial pressure, so that we can determine the final volume.

PV = nRT

P = ?

V = 37.6 L

n = 26 g x 1 mol/28 g = 0.93 moles

R = 0.0821 Latm/Kmol

T = 25 + 273 = 298 K

P =nRT/V = (0.93)(0.0821)(298)/37.6

P_initial = 0.604 atm

To find the change in volume, ∆V:

P1V1 = P2V2

(0.604 atm)(37.6 L) = (1.8 atm)(V2)

V2 = 12.6 L

Thus, ∆V = 37.6 L - 12.6 L = 25.0 L

W = -P∆V = -(1.8 atm)(25 L) = 45 L-atm x 101.325 J/L-atm = 4560 J