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Math

Susy H.

asked • 10/27/18

polynomial of degree

$3$ , with a zero of multiplicity $2$ at $x = 4$ and a zero of multiplicity $1$ at $x = - 5$ . The constant term is $- 400$

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Arturo O. answered • 05/23/20

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f(x) = A(x - 4)²(x + 5)

f(x) = A(x² - 8x + 16)(x + 5)

f(x) = A(x³ - 3x² - 24x + 80)

80A = -400

A = -5

f(x) = -5(x³ - 3x² - 24x + 80)

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