
Andy C. answered 10/27/18
Math/Physics Tutor
Well these are not inverse functions, they are COMPOSITE functions.
(f o g)(x) = f(g(x)) = 3 ( -4x + 7) - 5 <--- substitutes g INSIDE of f
= -12x + 21 - 5
= -12x + 16
So (f o g) (-4) = (-12)(-4) + 16 = 48 + 16 = 64
Note that g(-4) = (-4)(-4) + 7 = 16 + 7 = 23 and f(23) = 3(23)-5 = 69-5 = 64
Now for the INVERSE function.
Finds the inverse of y = f(x) = 3x - 5
STEP 1: SWAPS X and Y: x = 3y - 5
STEP 2: solves for x: x + 5 = 3y
(x+5)/3 = y
So the inverse is y = (x+5)/3
NOTE that when we compose f and its inverse we get:
3 [( x+5)/3] - 5
= x+5-5 <--- 3 cancels
= x
and
inverse compose f : [ (3x-5)+5] /3 = (3x)/3 = x
We get the identity function y=x
THIS MUST HAPPEN in order for the inverse to be correct