In a basketball game, BHS scored 60 points. The points were scored on 2- point baskets and 3- point baskets. The team made a total of 27 baskets. How many of each type were scored?

Answer 1

Let's represent this using algebraic expressions where x = # of 2-point baskets and y = # of 3-pointers:

2x + 3y = 60

x + y = 27 --> (x = 27 - y)

We could now solve by substitution:

2x + 3y = 60

2(27 - y) + 3y = 60

54 - 2y + 3y = 60

y = 6

If y=6, then x = 27 - y = 27 - 6 = 21.

BHS made 21 2-point baskets and 6 3-pointers.