need help to solve

Question

x^2+9x+8

Answer 1

Was the problem written x²+9x+8? We can solve by factoring. 8 and 1 are two factors of 8 that will add to give us 9, we will use those values to factor:

x²+9x+8 = 0

(x + 8) (x + 1) = 0

Now we set each factor equal to zero and solve:

x + 8 = 0

x = -8

x + 1 = 0

x = -1

Answer 2

i assume this is equal to zero? then use the quadratic equation to solve

(-b+-sqrt(b^2-4ac))/2a

=

(-9+-sqrt(81-32))/2

=

(-9+-sqrt(49))/2

=

(-9+-7)/2

=

x=(-9+7)/2 or x=(-9-7)/2

x=-2/2 or x=-16/2

x=-1 or x=-8

or

(x+1)(x+8)