L = length, W = width and P = perimeter
L = 3W + 18
Perimeter = 116 = 2(L + W) , i.e. L + W = 58
Now substitute
3W + 18 + W = 58
4W = 40
W = 10
L = 48
Zaviona W.
asked 10/23/18The perimeter of a rectangle is 116. The length is 18 more than 3 times the width. Find the dimensions
L = length, W = width and P = perimeter
L = 3W + 18
Perimeter = 116 = 2(L + W) , i.e. L + W = 58
Now substitute
3W + 18 + W = 58
4W = 40
W = 10
L = 48
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