Problem Page The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 cm , find its area. cm 2

Question

Problem Page The length of a rectangle is four times its width.  If the perimeter of the rectangle is  50 cm , find its area.  cm 2

Carol H. · Accepted Answer

Let w = the widthLet 4w = the lengthP = 2l + 2w50 = 2(4w) + 2w50 = 8w + 2w50 = 10w5 cm = w4w = 4(5) = 20cmA = lwA = 20(5)A = 100cm^2﻿

Paul M. · Answer

W = width, L = length, P = perimeter, A = areaL = 4WP = 2(L + W) = 50L + W = 254W + W = 25W = 5; L = 20A = LW = 20 * 5 = 100

2 Answers By Expert Tutors