A circled centered at the origin has a radius of 3. A line passes through points (-1, -3) and (4, 7). Write a system of equations and determine the point(s) of intersection.

Answer 1

The equation of the circle is $x^2+y^2=9$

The equation of the line = 2 = $\frac{(y-7)}{x-4}$ , i.e. y = 2x - 1

Substitute to get the quadratic $5x^2-4x-8=0$

The roots are approximately 1.73 and -.93.

I will leave it to you to compute the y co-ordinates.