Find the product of (5x-2),(2x-3) and (3x-1)

Answer 1

(5x-2)(2x-3)(3x-1) =

(10x^2 -19x + 6)(3x-1) =

30x^3 - 57x^2 + 18x

-10x^2 +19x - 6

30x^3 - 67x^2 + 37x - 6

check by synthetic division: 3x-1=0 is a factor so x=1/3

1/3 | 30 -67 37 -6

10 -19 6

________________

30 -57 18 0

30x^2 - 57x + 18 =

3( 10x^2 - 19x + 6) ( 5x - 2 )( 2x - 3 )

Answer 2

(5x - 2)(2x - 3) = 10x^2 - 4x - 15x + 6 = 10x^2 - 19x + 6

(10x^2 - 19x + 6)(3x - 1) = 30x^3 - 57x^2 + 18x - 10x^2 + 19x - 6 =

30x^3 + 47x^2 + 37x - 6