Find a point on the y-axis that is equidistant from the points (9, −9) and (2, 2)

Answer 1

Let (0,y) be the point then find the distance from that point to each of the other 2 points and set them equal to each other and solve for y

sqrt[(9-0)^2 + (-9-y)^2] = sqrt[(2-0)^2 + (2-y)^2] square both sides to get rid of the sqrt and simplify

81 + 81 -18y + y^2 = 4 + 4 -4y + y^2

154 = 14y

y = 11