I need help graphing this equation

Question

i don’t understand how to graph this line x-3y=0

Answer 1

Two points determine a line.

This line goes through the points (0,0) and (3,1) and extends in both directions.

Answer 2

The equation is given in standard form. You only need two points to graph a line. Normally, in that form, you set x to 0 and solve for y (to get y-intercept) and then set y to 0 and solve for x (to get x-intercept). Unfortunately, this would only give you 1 point (0,0). The other thing you can do is set y=1 (easy number for me to find an x value) and see what value of x would solve the equation x - 3y = 0

If y = 1 then we have x - 3(1) = 0

x - 3 = 0 . add 3 to both sides to isolate the x

x = 3

thus the point (3,1). This point and (0,0) would allow to graph the line.

You may ask why I didn't set x to 1 to find y...try it and you will understand why.

Answer 3

This is a special case equation to graph when you are plotting points. For example, with the equation

x - 3y = 0

When x = 0, y = 0. And when y = 0, x = 0. So we're stuck at (0,0). All you need to do is pick another value for x, or y. I will say if y = 1, what will x equal? So you will plot (3,1) for your third point after (0,0), (0,0). HOpe this helps.

Answer 4

There are a couple of ways to graph a line. You could use the slope-intercept method or use a table of values.

Slope-intercept: x - 3y = 0

-3y = -x

y = (1/3)x

The slope is 1/3 and the y-intercept is zero.

Plot (0,0) and then go up 1 and right 3 and place another point. Connect the points.