Let L = length, w = width, p = perimeter and A = area
L = 5 + 2w
p = (2(L + w ) = 190
L + w = 95
5 + 2w + w = 95
3w = 90
w = 30
L = 65
A = 65 * 30
Tequila W.
asked 10/17/18The perimeter of a rectangle is 190 feet find the dimensions if the length is 5 feet longer than two times the way then find the area of the rectangle
Let L = length, w = width, p = perimeter and A = area
L = 5 + 2w
p = (2(L + w ) = 190
L + w = 95
5 + 2w + w = 95
3w = 90
w = 30
L = 65
A = 65 * 30
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.