Raymond B. answered • 08/18/21

Math, microeconomics or criminal justice

a) 2

b) 3

c) 10

d) 5

total discs are 25

15 have neither Paul or Art

25-15 = 10 have at least one of Paul or Art = c)

5 have both, 10-5 = 5 have at most one of the two = d)

which also = a) + b) = 2+3 =5

a) = 7-5 = 2

b) = 8-5 = 3

draw two overlapping circles. the overlap = 5

the two circles are inside a rectangle, the area between the circles and the rectangle is 15

the two circles have 10 discs, 5 are the overlap, 5 are just one of each, Art or Paul