The sum of a number and 4 times its reciprocal is 13/3. Find both possible numbers

Answer 1

n + 4/n = 13/3

3n + 12/n = 13 multiply both sides by 3

3n^2 + 12 = 13n multiply both sides by n

3n^2 - 13n + 12 = 0

Can you solve for n and answer?