x^3y^2 = 1600
Differentiate implicitly using the product rule:
3x^2(dx/dt)y^2 + x^3(2y)(dy/dt) = 0
3(16)(-3)(25) + (64)(10)(dy/dt) = 0
-3600 + 640(dy/dt) = 0
dy/dt = 3600 / 640 = 5.625
Eric M.
asked 10/14/18How fast is the y-coordinate changing at that moment?
x^3y^2 = 1600
Differentiate implicitly using the product rule:
3x^2(dx/dt)y^2 + x^3(2y)(dy/dt) = 0
3(16)(-3)(25) + (64)(10)(dy/dt) = 0
-3600 + 640(dy/dt) = 0
dy/dt = 3600 / 640 = 5.625
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.