Patrick B. answered • 07/05/19
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3xy'+ 3 x' y-5 x'+6y^2 y'=0
3*2* y' + 3*-4*-1+ 5*-4+6(-1)^2*y'=0
6y' +12+-20+6y'=0
12 y' -8 =0
12y'=8
Y'=8/12
Y'=2/3
Eric M.
asked • 10/14/18assume x and y are functions of . Evaluate dy/dt for 3xy-5x+2y^3=-18 with the conditions dx/dt=-4, x=2, y=-1
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