If the smallest number of beans in a box is divisible by 5, 7 and 21 what is the total number in the box?

Question

Please show me the work

Answer 1

Factor 5:  5*1

          7:  7*1

         21: 7*3*1

 

Therefore, the smallest number divisible by 5, 7, and 21 is 5*7*3 = 105.   105/5 = 21, 105/7 = 15, 105/21 = 5.