How do I convert standard form to slope intercept form?

Question

I have a test soon and I don't fully understand this concept- help please!

Answer 1

Standard form:

 

Ax + By = C

 

Slope-intercept form:

 

y = mx + b

 

To convert Standard form to slope-intercept form, solve the standard form for y:

 

Ax + By = C

 

Subtract Ax from both sides

 

By = -Ax + C

 

Divide both sides by B:

 

y = (-A/B)x + (C/B)

 

y = mx + b

 

where m = -A/B and b = C/B.

 

Example:

 

-6x + 2y = 9     [Standard form]

 

2y = 6x + 9

 

y = 3x + 9/2     [slope-intercept form]