Write an equation of the line that passes through (−3,3) and is perpendicular to the line 2y=8x−6. How would I do that?

Answer 1

2y = 8x - 6

So, y = 4x - 3 (Slope = 4)

Slope of perpendicular line = -1/4

Equation of line: y-3 = (-1/4)(x-(-3))

y-3 = (-1/4)x - 3/4

y = (-1/4)x + 9/4