find two numbers whose sum is 42, if the larger number is three times less than twice the smaller number

Answer 1

Greetings! Lets solve this shall we ?

So, we must find the two numbers that satisfy this system of equations. First, we must translate this system into mathematical equations. Then,

x + y = 42

y = 2x - 3.............We use the Substitution method to solve this system such that

x + (2x - 3) = 42...............Add like terms such that

3x - 3 = 42...............Then add 3 to both sides such that

3x = 45................Then divide 3 such that

x = 15

Now we substitute 15 into the equation such that

15 + y = 42..............Then subtract 15 such that

y = 27

I hope this helped!