The sum of four consecutive even integers is -108?

Question

I need the answer for a project that I must make a perfect grade on.

Answer 1

Hello, thank you for taking the time to post your question!

The key on this type of question is to set up an algebraic expression that you can use to model the underlying situation that it’s asking about. For this one we have

x + (x + 2) + (x + 4) + (x + 6) = -108     because we know that when the 4 values are added together thy have to be equal to -108

solving that algebraically for the value of x then I get

(x + x + x + x) + (2 + 4 + 6) = -108

4x + 12 = -108

4x = -120

x = -30

that means that the sequence of consecutive even integers here begins at -30, so the 4 values are

-30, -28, -26, -24

I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

the integers are x, x+2, x+4, and x+6 where x is an even integer

x+x+2+x+4+x+6=-108

4x+12=-108

4x=-108-12

4x=-120

-120/4=-30,

x=-30

x+2=-28

x+4=-26

x+6=-24

-30, -28, -26, and -24 are the four consecutive integers

check:-30+(-28)+(-26)+(-24)=-108