you are making 100 L of 48% alcohol solution by mixing 40% alcohol and 60% alcohol. how many litres of each must be used?

Question

you need to know how many litres of 40% alcohol and 60% alcohol must be used.

 

Answer 1

x = liters of 40% alcohol

100 - x = liters of 60% alcohol

 

Set this up as

 

40x + 60(100 - x) = 48(100)

 

Solve for x and finish from here.