Victoria V. answered 09/11/18
Tutor
5.0
(402)
Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG
Let's see if we can pick this apart...
"Five times the difference" = 5(x-y)
"difference of twice a number and three" = 2x-3
So we have: 5(2x-3)
"decreased by the sum of" would be to subtract (a + b)
"the sum of the number and eight" (x + 8)
Now we have: 5(2x-3) - (x+8)= 13
Distribute the 5 into (2x-3) and the "-" into (x+8)
10x - 15 - x - 8 = 13
Combine like terms:
9x - 23 = 13
Add 23 to both sides
9x = 36
Divide both sides by 9
x=4