The length of a rectangle is 1 ft more than double the width, and the area of the rectangle is 66 ft2 . Find the dimensions of the rectangle.

Question

The length of a rectangle is
1 ft
more than double the width, and the area of the rectangle is
66 ft2
. Find the dimensions of the rectangle.

Answer 1

The length of a rectangle is 1 ft more than double the width

 

l = 2w + 1

 

area of the rectangle is
66 ft2

 

A = 2l + 2w = 66 ft^2

 

Substitute:

 

66 ft^2 = 2(2w + 1) + 2w

 

66 ft^2 = 4w + 2 + 2w

 

66 ft^2 = 6w + 2

 

64 ft^2 = 6w

 

w = 10.67 ft

 

l = 22.33 ft