
Quang H. answered 09/28/14
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Math and Science Tutor
So a company charges a fee per day and a fee per mile of rental. Jon rented for 6 days and 400 miles, and was charged $410, so we can come up with:
6d + 400m = 410
where d is the amount of money charged per day and m is the amount of money charged per mile.
Amanda rented for 5 days and 280 miles and was charged $323, so we can come up with:
5d + 280m = 323
So now we have 2 equations that each have 2 different variables, so we need to eliminate one of the variables. So what we can do is this: we multiply all of the terms in the first equation by 5 and all of the terms in the second equation by 6, so that both equations contain 30d, like this:
5 x [6d + 400m = 410] = 30d + 2000m = 2050
and
6 x [5d + 280m = 323] = 30d + 1680m = 1938
So now we have 2 new equations that both contain 30d, so we can subtract one from the other to eliminate 30d, like this:
30d + 2000m = 2050
- ( 30d + 1680m = 1938)
_________________________
0 + 320m = 112
So now we are left with:
320m = 112
and solving for m, we get:
m = 0.35
So the mileage charge is $0.35. To find the daily rental charge, you can plug in what we found for m into one of the original equations and solve for d:
5d + 280m = 323
5d + 280(0.35) = 323
5d + 98 = 323
5d = 225
d = 45
And so the daily rental charge is $45.